Using resonance, select the most acidic protons in the hexane-2,4-dione molecule. the most acidic proton is the one that, upon removal, will yield the most stable conjugate base.
check all that apply.
[hexane-2,4-dione molecule with protons numbered as follows according to iupac nomenclature: protons on c1 are numbered 1 through 3, protons on c3 are numbered 4 and 5, protons on c5 are numbered 6 and 7, protons on c6 are numbered 8 through 10.]

check all that apply.

protons 1, 2, or 3
protons 4 or 5
protons 6 or 7
protons 8, 9, or 10

Protons 4 or 5 are most acidic.

Explanation:

As mentioned there are four types of hydrogen in Hexane-2,4-dione.

The numbering are shown in the figure for your better understanding.

As shown in the figure if we remove the proton from carbon number 3 (protons number 4 or 5), it will result in formation of a carbanion. This carbanion is stabilized due to presence of -I group oxygen and there is possibility of resonance (as shown).

Thus protons 4 or 5 are most acidic.

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation:

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.