If a gaseous mixture is made by combining 1.55 g ar and 1.80 g kr in an evacuated 2.50 l container at 25.0 ∘ c, what are the partial pressures of each gas, p ar and p kr , and what is the total pressure, p total , exerted by the gaseous mixture

Partial Pressure Ar = 0.379 atm

Partial Pressure Kr = 0.210 atm

P total = 0.589 atm

Explanation:

First let's convert the masses of both gases to moles, using their respective atomic weight:

Now we can calculate the partial pressure of each gas, using PV = nRT:

P = 0.379 atm

P = 0.210 atm

Finally, the total pressure is the sum of the partial pressure of each gas:

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