![\Delta H=[(B.E_{H-H})+(2\times B.E_{C=O})]-[(2\times B.E_{O-H})+(1\times B.E_{C\equiv C})]](/tpl/images/0406/9090/bf0d1.png)
= enthalpy change
= 436 kJ/mol
= 463 kJ/mol
= 799 kJ/mol
= 839 kJ/mol![\Delta H=[(436kJ/mol)+(2\times 799kJ/mol)]-[(2\times 463kJ/mol)+(1\times 839kJ/mol)]](/tpl/images/0406/9090/6bfd0.png)
Ineed
use bond energies to calculate the enthalpy change for the following reaction.
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Answers: 1
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