Hydroperoxyl radicals (ho2) react rapidly with ozone to produce oxygen and oh radicals: $$ho2(g)+o3(g) o(g)+2o2(g) the rate of this reaction was studied in the presence of a large excess of ozone. plot the below data to determine the pseudo-first-order rate constant and the second-order rate constant. this reaction is first order for each reactant.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.