Write a balanced equation for the reaction that occurs in each of the following cases: (a) potassium metal is exposed to an atmosphere of chlorine gas. (b) strontium oxide is added to water. (c) a fresh surface of lithium metal is exposed to oxygen gas. (d) sodium metal reacts with molten sulfur.

The equations of the above reactions are shown below

Explanation:

(a)

2K(s) + Cl2(g) ==> 2 KCl(s)

(b)

SrO(s) + H2O(aq) ==> Sr(OH)2(aq)

(c)

4Li(s) + O2(g) ==> 2Li2O(s)

(d)

2Na(s) + S (l) ===> Na2S

pop pop pop on a opp

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72