If 0.771 g of o3 reacts with 0.663 g of no, how many grams of no2 will be produced?

Mass = 0.92 g

Explanation:

Given data:

Mass of O₃ = 0.771 G

Mass of NO₂ = 0.663 g

Mass of NO₂ produced = ?

Solution:

Chemical equation:

O₃ + NO → NO₂ + O₂

Number of moles of O₃ :

Number of moles = mass/ molar mass

Number of moles = 0.771 g/ 48 g/mol

Number of moles = 0.02 mol

Number of moles of NO:

Number of moles = mass/ molar mass

Number of moles = 0.663 g/ 30 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of NO₂ with NO and O₃ .

                NO       :        NO₂

                 1           :         1

              0.02        :      0.02

                O₃          ;        NO₂

                1             :         1

            0.02          :         0.02

Mass of NO₂:

Mass = number of moles × molar mass

Mass = 0.02 mol × 46 g/mol

Mass = 0.92 g

a boiling water reactor does not boil the water. a pressurized water reactor boils the water faster. a pressurized water reactor is heated directly by the core. a pressurized water reactor does not use fission.