Pentane is a small liquid hydrocarbon, between propane and gasoline in size at c5h12. the density of pentane is 0.626 g/ml and its enthalpy of combustion is δh°comb = –3535 kj/mol. estimate the fuel value and the fuel density of

Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and   respectively.

Explanation :

Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).

As we are given that:

Fuel value =

Molar mass of pentane = 72 g/mol

Fuel value =

Fuel value = 49.09 kJ/g

Now we have to calculate the fuel density of pentane.

Fuel density = Fuel value × Density

Fuel density = (49.09 kJ/g) × (0.626g/mL)

Fuel density = 30.73 kJ/mL =

Thus, the fuel density of pentane is

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

the correct answer would be b. amelia, because the particals of gas move really fast (charged particals) and gas also has a lot of room (particals move independently) so the only answer that has both of those is amelia's.