Determine the ph at the equivalence (stoichiometric) point in the titration of 27 ml of 0.24 m c6h5sh(aq) with 0.22 m naoh(aq). the ka of thiophenol is 3.2 x 10-7.

6.5 slightly acidic

Explanation:

pH =pka   -  log  [acid] / [base]

pH =6.49   -   log[0.224]/[0.22]

6.59-0.0377

6.45.

answer; talc and gypsum;

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.