If 28.64g of n2 reacts with 8.42g of h2 to produce nh3. what is the limiting reactant

nitrogen is limiting reactant

Explanation:

Given data;

Mass of nitrogen = 28.64 g

Mass of hydrogen = 8.42 g

Limiting reactant = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Number of moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles = 28.64 g / 28 g/mol

Number of moles = 1.02 mol

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 8.42 g / 2 g/mol

Number of moles = 4.21 mol

Now we compare the moles ammonia with hydrogen and nitrogen

                                N₂       :      NH₃

                                  1         :        2

                                   1.02   :      2/1 ×1.02 = 2.04 mol

                                   H₂       :      NH₃

                                     3        :        2

                                     4.21     :      2/3×4.21 = 2.8 mol

The number of moles of ammonia produced by nitrogen are less so it will limiting reactant.

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