In a 108.40 g empty beaker, 2.70 g of sodium reacts with an excess solution of iron ( iii ) acetate . after the reaction, the liquid is poured off and only the iron remains in the beaker and is left out overnight to dry. the next day the iron and the dry beaker have a mass of 110.28g. a calculate the theoretical yield of the iron produced a b calculate the percent yield of iron c if the percent yield is actually 93.1% , how much iron would have formed?

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.