Hydrogen gas p1=15 psia, t1= 80 degree f. compressed at a rate of 20 ft3/min in a hot environment until p2= 75.3 psig. heat is introduced at a rate of 20 btu/min and the change in entropy is 0.268 btu/min-r.

t1= 540r, h1= 3660.9, u1=2588.5, sp. heat = 31.232

(a) what is final t in r?

(b) what is the work equivalent hp if the system is non flow?

(c) work if the system is steady flow in btu/min?

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

fe 55.85 g/mol and h2o 18.02 g/mol.

the answer your looking for is c).