What is the amount of oxygen found in 13.15 grams of sodium acetate.

5.3 g

Explanation:

Data Given:

Sodium acetate CH₃COONa = 13.5 g

Amount of oxygen = ?

Solution:

Molecular weight calculation:

CH₃COONa = 12 + 1 x 3 + 12  + 16 x 2 + 23

CH₃COONa = 82 g/mol

Mass contributed by oxygen = 32 g

calculate the mole  percent composition of oxygen in sodium acetate

Since the percentage of compound is 100

So,

                Percent of Oxygen = 32 / 82 x 100

                Percent of Oxygen = 39 %

it means that for ever gram of sodium acetate there is 0.39 g of oxygen is present.

So, for 13.5 g the mass of Oxygen well be

            mass of Oxygen = 0.39 x 13.5

            mass of Oxygen = 5.3 g

it is called acid bonding

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.