Match the chromatography term with its definition. the volume of solvent traveling through the column per unit time. the elapsed time between sample injection and detection. the time required by a retained solute to travel through the column beyond the time required by the unretained solvent. the distance traveled by the solvent per unit time. describes the amount of time that a sample spends in the stationary phase relative to the mobile phase. it is sometimes also called the capacity factor or capacity ratio. volume of the mobile phase required to elute a solute from the column. ratio of the adjusted retention times or retention factors of two solutes. it is sometimes also called the separation factor. the ratio of the solute concentrations in the mobile and stationary phases.

The statements are definitions to chromatography terms which have been highlighted below.

Explanation:

Match the chromatography term with its definition.

Volumetric Flow Rate = The volume of solvent traveling through the column per unit time.

Retention time = The elapsed time between sample injection and detection.

Adjusted Retention Time = The time required by a retained solute to travel through the column beyond the time required by the un -retained solvent.

Linear Flow Rate = The distance traveled by the solvent per unit time.

Retention factor = Describes the amount of time that a sample spends in the stationary phase relative to the mobile phase. It is sometimes also called the capacity factor or capacity ratio.

Relative Volume = Volume of the mobile phase required to elute a solute from the column.

Relative Retention = Ratio of the adjusted retention times or retention factors of two solutes. It is sometimes also called the separation factor.

Partition coefficient = The ratio of the solute concentrations in the mobile and stationary phases.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .