What concentrations of acetic acid (pka = 4.76) and acetate would be required to prepare a 0.15 m buffer solution at ph 5.0? note that the concentration and/or ph value may differ from that in the first question. strategy 1. rearrange the henderson-hasselbalch equation to solve for the ratio of base (acetate) to acid (acetic acid), [a–]/[ha]. 2. use the mole fraction of acetate to calculate the concentration of acetate. 3. calculate the concentration of acetic acid. step 1: rearrange the henderson hasselbalch equation to solve for (a-)/(ha) if the solution is at ph 5.0

What is the percentage by mass of silicon (si) in iron aluminum silicate (fe3al2(sio4)3)?

13. calculate the initial concentration (before precipitation) of carbonate ions after the addition of each 0.05 ml of solution b to the 1.00 l beaker of solution a. divide the work among group members and write the answers in the table in model 3. assume the volume change as solution b is added is negligible. 14. notice the initial concentrations of zn2+ - and cu2+ in the table in model 3. a. explain how these were obtained from the data in model 2. b. as solution b is added and precipitates form, do these initial concentrations change? 15. use the data in model 2 to indicate the presence of precipitate (either znco3 or cuco3) after each 0.05 ml addition of solution b in model 3. 16. use the initial concentrations of carbonate ions and zinc ions to calculate the reaction quotient, qsp for the zinc carbonate scenarios in model 3. divide the work among group members and write the answers in the table in model 3. 17. use the initial concentrations of carbonate ion and copper(ii) ions to calculate the qsp for the copper(ii) carbonate scenarios in model 3. divide the work among group members and write the answers in the table in model 3.

Asample of ammonia reacts with oxygen as shown. 4nh3(g) + 5o2(g) 4no(g) + 6h2o(g) what is the limiting reactant if 4.0 g of nh3 react with 8.0 g of oxygen? o2 because it produces only 0.20 mol of no. nh3 because it produces only 0.20 mol of no. o2 because it produces two times less no than nh3. nh3 because it produces three times more no than o2.