Asolution has a (oh-) = 8.6 × 10-5 the poh=, ph=, (h+)=

POh is calculated by the negative logarithm of hydroxide ions concentration. From the given value, we have:

pOH = -log(8.6 x 10 ^-5)
pOH = 4.07

To calculate the pH we use the relation of pOH and pH, expressed as:

14 = pOH + pH
pH = 14 - 4.07 = 9.93
pH = -log [H+]
[H+] = 10^-9.93 = 1.16 x 10^-3 M

A) the enthralling of formation for pure element in its standard state is always positivehope this : )