Bi undergoes four decay reactions: α, β, β, α. step 1. undergoes α decay to give in the second step, tl-210 undergoes β decay. what is the product of this step? symbol = mass number = atomic number =

Pb-210 that lead-210 is the product of second step.

Explanation:

Alpha decay : When a larger nuclei decays into smaller nuclei by releasing alpha particle. In this process, the mass number and atomic number is reduced by 4 and 2 units respectively.

General representation of alpha decay :

Beta decay : In this process, a neutron is converted into a proton and an electron. In this decay, the atomic number is increased by 1 unit.

General representation of beta decay :

Step 1. Bi undergoes α decay;

81 = Z-2

Z = 83

210 = A - 4

A = 214

Step 2: Tl-210 undergoes β decay:

Pb-210 that lead-210 is the product of second step.

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

the answer is a and have a great day