41ca decays by electron capture. the product of this reaction undergoes alpha decay. what is the product of this second decay reaction? 41ca decays by electron capture. the product of this reaction undergoes alpha decay. what is the product of this second decay reaction? ti cl sc ar ca

Cl

Explanation:

⁴¹Ca has an atomic number equal to 20, it means that it has 20 protons and 20 electrons ad its neutral state. In the decay by electron capture, it will lose one electron and will become a cation, but the mass (41) and the atomic number will remain the same.

When Ca⁺ undergoes alpha decay, it will lose an alpha particle, which has mass 4 and 2 protons.

⁴¹₂₀Ca⁺ → ³⁷₁₈X⁺ + ⁴₂α

To be stable, X will lose a proton and will become ³⁷₁₇X. The element which has atomic number 17 is chlorine, Cl.

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explanation:

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answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :