At a certain temperature, 0.760 mol so3 is placed in a 1.50 l container. 2so3(g) = 2so2(g) + o2(g)at equilibrium, 0.130 mol o2 is present. calculate kc.

Explanation:

Moles of SO₃ = 0.760 mol

Volume = 1.50 L

[SO₃] = 0.5067 M

Considering the ICE table for the equilibrium as:

Given:    

Equilibrium concentration of  O₂ = 0.130 mol

Volume = 1.50 L

[O₂] = x = 0.0867 M

[SO₂] = 2x = 0.1733 M

[SO₃] = 0.5067-2x = 0.3334 M

The expression for the equilibrium constant is:

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.

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hope it ,

bioteacher101