Be sure to answer all parts. enter your answers in scientific notation.

the following values are the only allowable energy levels of a hypothetical one-electron atom:

e6 = −2.0×10−19 j

e5 = −7.0×10−19 j

e4 = −11.0×10−19 j

e3 = −15.0×10−19 j

e2 = −17.0×10−19 j

e1 = −20.0×10−19 j

(a) if the electron were in the n = 5 level, what would be the highest frequency (and minimum wavelength) of radiation that could be emitted?

frequency-

wavelength-

(b) if the electron were in the n = 1 level, what would be the shortest wavelength (in nm) of radiation that could be absorbed without causing ionization?

a) f = 3.02x10¹⁵ s⁻¹, and λ = 99.4 nm.

b) 99.4 nm

Explanation:

a) The energy of radiation is given by:

E = h*f

Where h is the Planck constant (6.626x10⁻³⁴ J.s), and f is the frequency. To have the highest frequency, the energy must be the highest too, because they're directly proportional. So we must use E = -E1 = 20x10⁻¹⁹ J

20x10⁻¹⁹ = 6.626x10⁻³⁴xf

f = 3.02x10¹⁵ s⁻¹

The wavelenght is the velocity of light (3.00x10⁸ m/s) divided by the frequency:

λ = 3.00x10⁸/3.02x10¹⁵

λ = 9.94x10⁻⁸ m = 99.4 nm

b) To have the shortest wavelength, it must be the highest energy and frequency, so it would be the same as the letter a) 99.4 nm.

girl imma just put my comment here because i need a couple point okurrttt