Identify the final concentrations of each species following the addition of 1.0 m koh to a 2.0 m hf solution. hf ( aq ) + koh ( aq ) ⟶ kf ( aq ) + h 2 o ( l ) initial 2.0 m 1.0 m 0 m change final ? ? ?

Answer : The final concentration of KOH, HF and KF are 0 M, 1.0 M and 1.0 M respectively.

Explanation :

The given chemical reaction is:

Initial conc.   2.0 M       1.0 M            0 M

Final conc.    1.0 M         0 M             1.0 M

When 1.0 M of KOH react with 2.0 M HF  then 1.0 M KOH will react with 1.0 M HF to form 1.0 M KF and 1.0 M HF remain unreacted.

So, the final solution contains 1.0 M HF and 1.0 M KF that means the solution contains equal amount of weak acid and salt.

Therefore, the final concentration of KOH, HF and KF are 0 M, 1.0 M and 1.0 M respectively.

the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.