What mass of feso4^2- x 6h20 (molar mass=260g/mol) is required to produce 500 ml of a .10m iron (ii) sulfate solution.
a.) 9g
b.) 13g
c.) 36g
d.) 72g

The correct option is: B. 13g

Explanation:

Given: Molar mass of iron (II) sulfate: m = 260g/mol,

Molarity of iron (II) sulfate solution: M =  0.1 M,

Volume of iron (II) sulfate solution: V = 500 mL = 500 × 10⁻³ = 0.5 L           (∵ 1L = 1000mL)

Mass of iron (II) sulfate taken: w = ? g

Molarity:

Here, n- total number of moles of solute, w - given mass of solute, m- molar mass of solute, V- total volume of solution in L

∴ Molarity of iron (II) sulfate solution:  

⇒  

⇒  

⇒  mass of iron (II) sulfate taken:

Therefore, the mass of iron (II) sulfate taken for preparing the given solution is 13 g.

1 is the answer to this problem

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.