I. determine the mass of reactants and products that will be needed if one mole of p4(s) reacts completely, as follows

p4(s) + 6 h2(g) →4 ph3(g)

ii. what is the total mass of the reactants? what is the mass of the products?

iii. what principle is illustrated by this example?

if someone could really me with explanation as well you very much

I. Reagents:

P₄= 123.88 g

H₂ = 12 g

Products:

PH₃= 135.88g

II. Total reagents = 135.88 g

Total products = 135.88 g

III. The principle of conservation of mass

Explanation:

I. First, the molar masses of all reagents and all reaction products are calculated:

• mP₄ = 4 x mP = 4 x 30.97g = 123.88 g / mol

• mH₂ = 2 x mH = 2 x 1.00g = 2 g / mol

• mPH₃ = 4 x mH + m P = 3 x 1.00g + 30.97g = 33.97 g / mol

Having the equation balanced, it can be seen that in order for one mole to react completely of P₄, 6 moles of H₂ must react, and 4 moles of PH₃ will be produced. With the molar masses, we obtain the reacting masses of each reagent and the mass of product that is formed:

Reagents:

P₄: 1 mol ≡ 123.88 g

H₂: 6 moles ≡ 12 g

Products:

PH₃: 4 moles ≡135.88g

II. We add the total mass of the reagents:

Total reagents = mP₄ + mH₂ = 123.88 g + 12 g = 135.88 g

As the reaction product is only PH₃, the total mass of products is 135.88 g

III. It is seen that the mass of reagents necessary to produce the reaction is equal to the mass of product obtained. Therefore, the principle illustrated with this example is the principle of conservation of mass, it says that “In an isolated system, during any ordinary chemical reaction, the total mass in the system remains constant, that is, the mass Consumption of reagents is equal to the mass of the products obtained ”

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

it's filtration, but this is an assumption so my apologies if i got this