100 ml of a 1 m hcl and 100 ml of a 5m nacl solution are mixed. what is the final molarity of the chloride ions?
a.) .5m
b.) 2m
c.) 3m
d.) 4m

3M

Explanation:

Because HCl and NaCl do not react with each other, the final number of the Cl⁻ ions is equal to the sum of the ions of each starting reagent:

Cl⁻ moles from HCl ⇒0.100 L * 1 M = 0.1 moles Cl⁻

Cl⁻ moles from HCl ⇒0.100 L * 5 M = 0.5 moles Cl⁻

We add up the volumes from each solution:

And finally calculate the final molarity of Cl⁻ ions:

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.