7.66 write balanced equations for the following reactions: (a) potassium oxide with water, (b) diphosphorus trioxide with water, (c) chromium(iii) oxide with dilute hydrochloric acid, (d) selenium dioxide with aqueous potassium hydroxide

The balanced chemical equations for the reactions are

(a) K₂O + H₂O  → 2KOH

(b) P₂O₃ + 3H₂O → 2H₃PO₃

(c) Cr₂O₃ + 6HCl → 2CrCl₃ + 3H₂O

(d) SeO₂ + 2KOH → K₂SeO₃ + H₂O

From the question

We are to write a balanced equations for the given reactions

The reaction between potassium oxide and water gives potassium hydroxide

The balanced chemical equation for the reaction between potassium oxide and water is

K₂O + H₂O  → 2KOH

The reaction between diphosphorus trioxide with water gives phosphorous acid

The balanced chemical equation for the reaction between diphosphorus trioxide with water is

P₂O₃ + 3H₂O → 2H₃PO₃

The reaction between chromium(III) oxide with dilute hydrochloric acid produces chromium(II) chloride and water

The balanced chemical equation for the reaction between chromium(III) oxide with dilute hydrochloric acid is

Cr₂O₃ + 6HCl → 2CrCl₃ + 3H₂O

The reaction between selenium dioxide with aqueous potassium hydroxide gives potassium selenite and water

The balanced chemical equation for the reaction between selenium dioxide with aqueous potassium hydroxide

SeO₂ + 2KOH → K₂SeO₃ + H₂O

Hence, the balanced chemical equations for the reactions are

(a) K₂O + H₂O  → 2KOH

(b) P₂O₃ + 3H₂O → 2H₃PO₃

(c) Cr₂O₃ + 6HCl → 2CrCl₃ + 3H₂O

(d) SeO₂ + 2KOH → K₂SeO₃ + H₂O

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