Mothballs are comprised primarily of naphthalene (c10h8). when 1.025 g of naphthalene burns in a bomb calorimeter, the temperature rises from 24.25 degrees celsius to 32.33 degrees celsius. find the change in energy for the combustion of a mole of naphthalene. the heat capacity of the bomb calorimeter is 5.11 kj/degree celsius.

The change in energy for the combustion of a mole of naphthalene is 79 kJ

Explanation:

An excersise where you have to apply the Heat Capacity formula

C =  Q . ΔT

where C is Heat Capacity and Q is Heat

ΔT means (T° final - T° initial)

5.11 kJ/°C = Q (32.33°C - 24.25°C)

5.11 kJ/°C = Q (32.33°C - 24.25°C)

5.11 kJ/°C = Q . 8.08°C

5.11 kJ / 8.08°C = Q

0.632 kJ = Q

This heat is released by 1.025 grams of naphtalene.

Molar mass Naphtalene : 128.17 g/m

1.025 g / 128.17 g/m = 0.008 moles

This are the moles, so we have to divide heat/moles to get the change in energy for one mole.

0.632 kJ/0.008 mol = 79 kJ/m

is there multiple choice answers?

i believe the answer is a.