The mass of solute per 100 ml of solution is abbreviated as (m/v). mass is not technically the same thing as weight, but the abbreviation (w/v) is also common. how many grams of sucrose are needed to make 765 ml of a 31.0 % (w/v) sucrose solution?

There are needed 237.15 g of sucrose.

Explanation:

The 31.0 % (w/v) of the sucrose solution means that in 100 ml of solution, you have 31 g of solute, in this case sucrose.

So you want to make a solution with 765 mL.

Let's think the rule of three:

100 mL solution__contain __31 g sucrose

765 mL solution (765 . 31 ) /100 = 237.15 g

2b2t

explanation:

2b2t

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.