Agalvanic (voltaic) cell has the generic metals x and y as electrodes. x is more reactive than y , that is, x more readily reacts to form a cation than y does. classify the descriptions by whether they apply to the x or y electrode.

(a) anode
(b) cathode
(c) electrons in the wire flow toward
(d) electrons in the wire flow away
(e) cations from salt bridge flow toward

(a) X electrode

(b) Y electrode

(c) Y electrode

(d) X electrode

(e) Y electrode

Explanation:

A galvanic (voltaic) cell has the generic metals X and Y as electrodes. X is more reactive than Y, that is, X more readily reacts to form a cation than Y does.

In the X electrode occurs the oxidation whereas in the Y electrode occurs the reduction.

Oxidation: X(s) → X⁺ⁿ(aq) + n e⁻

Reduction: Y⁺ˣ(aq) + x e⁻ → Y(s)

Classify the descriptions by whether they apply to the X or Y electrode.

(a) anode. Is where the oxidation takes place (X electrode).

(b) cathode. Is where the reduction takes place (Y electrode).

(c) electrons in the wire flow toward. Electrons in the wire flow toward the cathode (Y electrode).

(d) electrons in the wire flow away. Electrons in the wire flow away from the anode (X electrode).

(e) cations from salt bridge flow toward. Cations from the salt bridge flow toward the cathode (Y electrode) to maintain the electroneutrality.

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.

i believe you are right for all except the 3rd ( look at sqdancefan his answer is much better)