Agold ring was purchased from a street vendor for a ridiculously low price. the buyer has brought the ring to you to conform its metal content. you have found the mass of the ring to be 23.46 h and its volume to be 2.25 cm3. what do you tell the buyer?

Explanation:

We are given:

Mass of liquid = 23.46 g

Volume occupied by the ring =

Density of gold ring = D

Original density of gold =

We will tell the buyer that gold ring purchased from him is too adulterated with other metals which have reduced its density indication that it is an artificial gold ring.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%