Free-energy change, δg∘, is related to cell potential, e∘, by the equationδg∘=−nfe∘where n is the number of moles of electrons transferred and f=96,500c/(mol e−) is the faraday constant. when e∘ is measured in volts, δg∘ must be in joules since 1 j=1 c⋅v.1. calculate the standard free-energy change at 25 ∘c for the following reaction: mg(s)+fe2+(aq)→mg2+(aq)+fe(s)expres s your answer to three significant figures and include the appropriate units.2. calculate the standard cell potential at 25 ∘c for the reactionx(s)+2y+(aq)→x2+(aq)+2y(s)w here δh∘ = -675 kj and δs∘ = -357 j/k .express your answer to three significant figures and include the appropriate units.

a)

b)

Explanation:

a) The reaction:

The free-energy expression:

The element wich is reduced is the Fe and the one that oxidates is the Mg:

The electrons transfered (n) in this reaction are 2, so:

b) If you have values of enthalpy and enthropy you can calculate the free-energy by:

with T in Kelvin

what is the question here. i think you messed up.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o