Oxalic acid reacts with sodium hydroxide according to the following equation:
h2c2o4 + 2 naoh...
Chemistry, 27.11.2019 07:31, BeautyxQueen
Oxalic acid reacts with sodium hydroxide according to the following equation:
h2c2o4 + 2 naoh → na2c20. + 2 h20
a 25.00 ml sample of the h2c2o solution required 19.62 ml of 0.341 m naoh for
neutralization. calculate the molarity of the acid.
Answers: 1
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