If 6.50 moles of an ideal gas has a pressure of 2.69 atm, and a volume of 64.27 l, what is the temperature of the sample in degrees celsius?

The temperature in degrees Celsius is 51.21ºC.

Explanation:

An ideal gas is a hypothetical gas whose pressure-volume-temperature

behavior can be completely accounted for by the ideal gas equation:

We want to know the temperature of the sample, which will be in Kelvin, so we rearrange the equation to give:

Knowing that:

p= 2.69 atm

n= 6.50 mol

V= 64. 27 L

and R, the gas constant is 0.082 L× atm ÷ mol×K

Now, we need to convert Kelvins to degrees Celsius. We use the following equation:

K= 324.36 K - 273.15ºC = 51.21 ºC

Therefore, the temperature of the sample is 51.21 degrees Celsius.

i would say b

explanation:

but i think i would need more information than that