The rate law for a hypothetical reaction is rate = k [a]2. when the concentration is 0.10 moles/liter, the rate is 2.7 × 10-5 m*s-1. what is the value of k?

Given:

rate = k [A]2

concentration is 0.10 moles/liter

rate is 2.7 × 10-5 M*s-1

Required:

Value of k

Solution:

rate = k [A]2

2.7 × 10-5 M*s-1 = k (0.10 moles/liter)^2

k = 2.7 x 10^-3 liter per mole per second

b. is the answer hoped i        

explanation: