Which of the following best describe the particles present in a 2.0 m aqueous solution of al(no3)3? 2 m al3+(aq) and 18 m no3-(aq)2 m al(no3)3(aq)2 m al3+(aq) and 6 m no3-(aq)2 m al3+(aq) and 3 m no3-(aq)

The correct answer is: 2M Al3+(aq) and 6 M NO3-(aq)

Explanation:

Step 1: Data given

2.0 M Al(NO3)3

Step 2:

Al(NO3)3 in water will dissociate as following:

Al(NO3)3 → Al^3+ + 3NO3^-

For 1 mol of Al(NO3)3 we will have 1 mol of Al^3+ and 3 moles of NO3^-

We know that the molarity of Al(NO3)3 = 2.0 M, this means 2.0 mol/ L

The mol ratio Al(NO3)3 and Al^3+ is 1:1 so the molarity of Al^3+ is 2.0 M

The mol ratio Al(NO3)3 and NO3^- is 1:3 so the molarity of NO3^- is 6.0M

The correct answer is: 2M Al3+(aq) and 6 M NO3-(aq)

there all right good

explanation: