If 25 ml of koh were needed to neutralize 15 ml of 3.5 m hbr, calculate the molarity of the base

2.1 M KOH is required.

Explanation:

It is an example of acid-base neutralization reaction.

KOH  +  HBr  ---->  KBr  +  

Base     Acid           Salt        

When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .

Molarity=

No.of moles= Molarity × Volume of the Particular Solution

Therefore,

------------------------------(1)

where

= Molarity of Acid

= Volume of Acid

= Molarity of Base

= Volume of Base

=3.5 M

=15 mL

=25 mL

=??(in M)

Plugging in Equation 1,

3.5 × 15 = × 25

=

=2.1 M

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2