Sodium metal reacts with water to form hydrogen gas: 2 na + 2 h2o -> 2 naoh + h2. 10 moles of na thrown into a large volume of water will produce

Only 10 mole of water will react with 10 mole of Na metal

and produce

                     10Na + 10H₂O > 10NaOH + 5H₂

Explanation:

2Na + 2H₂O > 2NaOH + H₂

Exothermic Reaction:

This reaction is supper exothermic and when sodium metal react with water it produce a lot of heat.

Limiting Reagent:

Limiting reagent is the amount of reactant in a chemical reaction that determines the amount of products that will be produce.

For instance we will use the same equation

2Na + 2H₂O > 2NaOH + H₂

The reaction shows that 2 mole of sodium combine with 2 mole of water and will produce 2 mole of NaOH and 1 mole of Hydrogen gas.

if we increase the amount of  water  to 4 mole then the same amount of product will form, and the extra water will remain unracted.

Similarly if we increase amount of Na to 4 mole then only 2 mole will react and will produce same amount.

Now

if we add 10 mole of Na to a large Volume of water following thing will happen

Given Reaction:

                  2Na + 2H₂O > 2NaOH + H₂

Data from Reaction:

                   2Na +  2H₂O > 2NaOH + H₂

                   2 mole   2mole                   2mole      1mole

Applying unity formula:

2 mole of Na will react with 2mole of water

So

                       2 mole of Na ≅ 2mole of H₂O

                       10 mole of Na = 10 mole of H₂O

So the same reaction will occur and produce NaOH and hydrogen gas

So, From the above reaction

                          2 mole of Na ≅ 2mole of NaOH

if 2 mole of Na produces 2 mole of NaOH then 10 mole will produce how much NaOH

apply the unity formula

2 mole of the Na ≅ 2 mole of NaOH

10 mole of the Na ≅ X mole of NaOH

so by cross multiplication

2 mole of Na x X mole of NaOH ≅ 2 mole of NaOH x 10 mole of the Na

we have to find moles of NaOH so by rearrangement of the above equation

X mole of NaOH = 2 mole x 10 mole

                                       2 mole

X mole of NaOH= 10 mole

So

10 mole of Na will produce 10 mole NaOH

For Hydrogen Gas that produce :

                         2 mole of Na ≅ 1 mole H₂

If 2 mole of Na produces 1 mole of H₂ then 10 mole will produce how much H₂

apply the unity formula

2 mole of the Na ≅ 1 mole of H₂

10 mole of the Na ≅ X mole of H₂

so by cross multiplication

2 mole of Na x X mole of H₂ ≅ 1 mole of H₂ x 10 mole of the Na

we have to find moles of H₂ so by rearrangement of the above equation

X mole of H₂ = 1 mole x 10 mole

                                       2 mole

X mole of H₂ = 5 mole

So

The following will be reaction if 10 moles Na thrown in large volume of water

Only 10 mole of water will react with it

                     10Na + 10H₂O > 10NaOH + 5H₂ and heat