Aluminum bromide reacts with chlorine gas to produce aluminum chloride and liquid bromide,
according to the chemical equation below:
2a1br3 + 3cl2 + 2alcl3 + 3br2
how many moles of aluminum chloride are made if 779 g of chlorine gas are consumed?

779 g of chlorine would produce 7.3 moles of AlCl₃

Explanation:

Given data:

Mass of chlorine gas = 779 g

Number of moles of Aluminium chloride formed = ?

Solution:

Chemical equation:

2AlBr₃ + 3Cl₂ → 2AlCl₃ + 3Br₂

Number of moles of chlorine:

Number of moles = mass/ molar mass

Number of moles = 779 g/ 71 g/mol

Number of moles = 11 mol

Now we will compare the moles of chlorine with Aluminium chloride.

                                Cl₂                    :            AlCl₃

                                  3                     :                2

                                  11                     :                 2/3×11 = 7.3 mol

779 g of chlorine would produce 7.3 moles of AlCl₃.