What is the balanced form fir na(s) + ao2(g) = na2o(s)

Balanced Chemical equation:

4Na + O₂ → 2Na₂O

Explanation:

Chemical equation:

Na + O₂ → Na₂O

Balanced Chemical equation:

4Na + O₂ → 2Na₂O

Four mole of sodium combine with one mole of oxygen and form two mole of sodium oxide.

Coefficient with reactant and products:

Na   4

O₂     1

Na₂O  2

Oxygen is present in group sixteen and have six valance electrons. while sodium is alkali metal and present in group one and have one valance electron.

Oxygen needs two electron to complete the octet while sodium need to lose the one electron to get the complete octet.

When oxygen is combine with sodium it gain its two valance electrons from two sodium atom and form anion while sodium loses its valance electron to wards oxygen and form cation. The bond form between them is ionic because one is metal and other is non metal and electrons are completely transfer from two sodium atom to one oxygen atom.

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: