How many miles of ammonia are need to produce 45.5 grams of water

1.69 moles of ammonia are needed to produced 45.5 g of water.

Explanation:

Given data:

Mass of water = 45.5 g

Moles of ammonia required = ?

Solution:

Chemical equation:

4NH₃ + 5O₂ → 4NO + 6H₂O

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles =   45.5 g/ 18 g/mol

Number of moles = 2.53 mol

Now we will compare the moles of water with ammonia.

                         H₂O                :           NH₃

                            6                 :              4

                        2.53                :              4/6×2.53 = 1.69 mol

1.69 moles of ammonia are needed to produced 45.5 g of water.

the answer is a and have a great day

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer