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A35.00−ml solution of 0.2500 m hf is titrated with a standardized 0.1775 m solution of naoh at 25°c. (a) what is the ph of the hf solution before titrant is added? (b) how many milliliters of titrant are required to reach the equivalence point? ml (c) what is the ph at 0.50 ml before the equivalence point? (d) what is the ph at the equivalence point? (e) what is the ph at 0.50 ml after the equivalence point?
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Chemistry, 22.06.2019 09:00, dante766
Achemist 16 drop copper metal from copper chloride solution. the chemist place is 0.50 g of aluminum foil in a solution containing 0.75 g of copper (ii) chloride. a single replacement reaction takes place. which statement explains the maximum amount of copper that the chemist can extract using this reaction?
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Chemistry, 22.06.2019 14:30, joejoefofana
Consider the reduction reactions and their equilibrium constants. cu+(aq)+e−↽−−⇀cu(s)pb2+(aq)+2e−↽−−⇀ pb(s)fe3+(aq)+3e−↽−−⇀fe(=6.2×108=4. 0×10−5=9.3×10−3 cu + ( aq ) + e − ↽ − − ⇀ cu ( s ) k =6.2× 10 8 pb 2 + ( aq ) +2 e − ↽ − − ⇀ pb ( s ) k =4.0× 10 − 5 fe 3 + ( aq ) +3 e − ↽ − − ⇀ fe ( s ) k =9.3× 10 − 3 arrange these ions from strongest to weakest oxidizing agent.
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Chemistry, 22.06.2019 23:00, lufung8627
Consider the reaction: 2al(s) + fe2o3(s) → al2o3(s) + 2fe(s) the δhf for fe2o3(s) = -824.3 kj/mole. the δhf for al2o3(s) = -1675.7 kj/mole. finish the equation. δhrxn = [(1)( kj/mole) + (2)( kj/mole)] - [(1)( kj/mole) + (2) ( kj/mole)]
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A35.00−ml solution of 0.2500 m hf is titrated with a standardized 0.1775 m solution of naoh at 25°c....
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