Chemistry, 21.11.2019 21:31, farhansayeed11
What change would you expect on the rate of the sn2 reaction of 1-iodo-2-methylbutane with cyanide ion if the nucleophile concentration is halved and the alkyl halide concentration is unchanged ?
Answers: 3
reaction, the rate law is -![Rate=k[1-iodo-2-methylbutane][CN^{-}]](/tpl/images/0385/0817/4535d.png)
![[CN^{-}]](/tpl/images/0385/0817/39859.png)
is concentration of 
![(Rate)_{initial}=k\times [1-iodo-2-methylbutane]_{initial}\times [CN^{-}]_{initial}](/tpl/images/0385/0817/260a5.png)
![Rate=k\times [1-iodo-2-methylbutane]_{initial}\times \frac{[CN^{-}]_{initial}}{2}=\frac{(Rate)_{initial}}{2}](/tpl/images/0385/0817/2a3f6.png)
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What change would you expect on the rate of the sn2 reaction of 1-iodo-2-methylbutane with cyanide i...
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