From the following data, calculate the average bond enthalpy for the noh bond: nh3(g) ¡nh2(g) 1 h(g) ¢h° 5 435 kj/mol nh2(g) ¡nh(g) 1 h(g) ¢h° 5 381 kj/mol nh(g) ¡n(g) 1 h(g) ¢h° 5 360 kj/mol

The average bond enthalpy for the N-H bond is 392 kJ/mol.

Explanation:

..[1]

..[2]

..[3]

On adding [1] , [2] and [3] , we get:

There three bonds N-H bond sin ammonia. Then average bond enthalpy of single N-H bond is :

The average bond enthalpy for the N-H bond is 392 kJ/mol.

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explanation:

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it