Assuming that gasoline is 100% isooctane, that isooctane burns to produce only co2 and h2o, and that the density of isooctane is 0.792 g/ml, what mass of co2 (in kilograms) is produced each year by the annual u. s. gasoline consumption of 4.6×1010l?

1.12 × 10¹¹ kg of CO₂

Explanation:

Let's consider the combustion of isooctane.

C₈H₁₈(l) + 12.5 O₂(g) ⇒ 8 CO₂(g) + 9 H₂O(l)

We can establish the following relations:

Then, for 4.6 × 10¹⁰ L of gasoline (assuming that gasoline is 100% isooctane):

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.