The stopcock connecting a 3.06 l bulb containing methane gas at a pressure of 9.61 atm, and a 6.65 l bulb containing oxygen gas at a pressure of 1.75 atm, is opened and the gases are allowed to mix. assuming that the temperature remains constant, the final pressure in the system is atm.

Answer : The final pressure in the system is 4.22 atm.

Explanation :

First we have to calculate the moles of methane.

where,

P = pressure of gas = 9.61 atm

V = volume of gas = 3.06 L

T = temperature of gas = T

= number of moles of methane gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

Now we have to calculate the moles of oxygen gas.

where,

P = pressure of gas = 1.75 atm

V = volume of gas = 6.65 L

T = temperature of gas = T

= number of moles of oxygen gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

Now we have to determine the final pressure in the system after mixing the gases.

where,

= final pressure of gas = ?

= final volume of gas = (3.06 + 6.65)L = 9.71 L

T = temperature of gas = T

R = gas constant

Now put all the given values in the ideal gas equation, we get:

Therefore, the final pressure in the system is 4.22 atm.

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong