Suppose that the molar concentrations for co and h2 at equilibrium are [co] = 0.03 m and [h2] = 0.04 m. use the formula [ch3oh]= kc[co][h2]2 calculate the concentration of ch3oh. express your answer to one decimal place and include the appropriate units.

[CH₃OH] = 1.1 M

Explanation:

Let's consider the synthesis of methanol at high temperature.

CO(g) + 2 H₂(g) ⇄ CH₃OH(g)

The equilibrium constant Kc is:

We know the concentrations at equilibrium, [CO] = 0.03M and [H₂] = 0.04 M. So, we can find [CH₃OH].

the dissolution of polymer can be thermodynamically described in 2 steps.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.