If two atoms have the same number of bonds, why would a compound with a lone pair of electrons on the central atom have smaller bond angles than a compound without a lone pair?

lone electron pairs cause greater repulsion than bonding pairs; therefore, angles between bonding pairs are increased.
both compounds would have the same bond angles because they have the same number of bonding electrons.
bonding pairs of electrons cause greater repulsion than lone pairs; therefore, angles between the bonding pairs are increased.
lone electron pairs cause greater repulsion than bonding pairs; therefore, angles between the bonding pairs are reduced.

The correct answer is lone electron pairs causes greater repulsion than bonding pairs therefore angles between the bonding pairs are reduced.

Explanation:

We all know that lone pair lone pair repulsion>lone pair bond pair repulsion>bond pair bond pair repulsion.

 lone pair of electrons present in central atom has greater magnitude of repulsion than that without lone pair.

 As a result presence of lone pair of electrons reduces the bond angle between the bonding pairs.

gold is my favorite solid.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2