Calculate the molality of isoborneol in the product if, a) the melting point of pure camphor is 179°c and the melting point taken from your sample is 165°c and b) the freezing point depression constant for camphor is 40°c kg/mol.

The molality of isoborneol in camphor is 0.53 mol/kg.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = = 165°C

Depression in freezing point =

Depression in freezing point  is also given by formula:

= The freezing point depression constant

m = molality of the sample

i = van't Hoff factor

We have: = 40°C kg/mol

i = 1 (  organic compounds)

The molality of isoborneol in camphor is 0.53 mol/kg.

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!