Chemistry, 20.11.2019 21:31, marlesly87
Ethylenediamine (en) forms an octahedral complex with ni2+(aq) with the formula [ni(en)3]2+. ni2+(aq) + 3 en ⇌ [ni(en)3]2+(aq) kf = 4.0 x 1018 if there are 0.16 mol [ni(en)3]2+ and 0.80 mol ethylenediamine at equilibrium in a 2-l solution, what is the concentration of ni2+(aq) in the solution?
Answers: 3
is the concentration of 
in the solution.![Ni^{2+}(aq) + 3 en\rightleftharpoons [Ni(en)_3]^{2+}(aq)](/tpl/images/0383/3334/4ce74.png)
![[Ni^{2+}]=x](/tpl/images/0383/3334/f3c8f.png)
![[[Ni(en)_3]^{2+}]=\frac{0.16 mol}{2 L}=0.08 mol/L](/tpl/images/0383/3334/80efd.png)
![[en]=\frac{0.80 mol}{2 L}=0.40 mol/L](/tpl/images/0383/3334/3eb02.png)
![K_f=\frac{[[Ni(en)_3]^{2+}]}{[Ni^{2+}][en]^3}](/tpl/images/0383/3334/2ab0f.png)
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Ethylenediamine (en) forms an octahedral complex with ni2+(aq) with the formula [ni(en)3]2+. ni2+(aq...
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