Chemistry, 20.11.2019 21:31, kayleedavis08

How much mass do 2.6 moles of gold contain

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answered: tladitidimatso1783

512.114 g

Explanation:

We are given;

Number of moles of gold as 2.6 moles

we are required to calculate the mass of gold

To answer the question, we need to understand the relationship between mass, molar mass and moles.To calculate number of moles of an element we divide mass of the element by its molar mass.That is; Moles = Mass ÷ molar massRearranging the formula;

Mass = Moles × molar mass

In this case;

Molar mass of Gold is 196.967 g/molTherefore;

Mass of Gold = 2.6 moles × 196.967 g/mol

= 512.1142 g

= 512.114 g

Thus, the mass of gold is 512.114 g

answered: Guest

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction: so₂cl₂ (g) = so₂ (g) + cl₂ (g) total

the moles at equilibrium: 1 - α α α = 1+α

concentrations: 1 - α α α = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

$k_{c}$ = $\frac{[so2cl2] x [cl2]}{[so2cl2]}$

or, $\frac{\alpha ^{2} }{(1-\alpha)v }$

or, $k_{c}$ = $\frac{\alpha ^{2} }{(1-\alpha) }$ (at v = 1l)

the reaction: so₂cl₂ (g) = so₂ (g) + cl₂ (g) total

the moles at equilibrium: 1 - α α α = 1+α

concentrations: (1 - α)/0.5 α/0.5 α/0.5 = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

$\frac{[so2cl2] x [cl2]}{[so2cl2]}$

or, $\frac{\alpha ^{2} }{(1-\alpha)0.5 }$

$\frac{\alpha ^{2} }{(1-\alpha) }$ = $\frac{\alpha ^{2} }{(1-\alpha) 0.5}$

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

answered: Guest

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.

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