)for a certain reaction, kc=0.514 and kf=38.2 m^-2 x s^-1 . calculate the value of the reverse rate constant, kr, given that the reverse reaction is of the same molecularity as the forward reaction.
express your answer with the appropriate units.

part b)

for a different reaction, kc=1.28×10^3 , kf=1.77×10^3 s^-1 , and kr=1.38 s^-1 . adding a catalyst increases the forward rate constant to 7.47×10^5 s^-1. what is the new value of the reverse reaction constant, k_r, after adding catalyst?
express your answer with the appropriate units.

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

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