Asample of gas in a balloon has an initial temperature of 37c and a volume of 1560 l. if the temperature changes to 82c , and there is no change of pressure or amount of gas, what is the new volume, v2, of the gas? in liters?
what celsius temperature, t2 , is required to change the volume of the gas sample in part a ( = 37 , = 1560 t1=37c, v1=1560l) to a volume of 3120 l? assume no change in pressure or the amount of gas in the balloon. in c?

First part: The new volume of the gas is 1786 Liters.

Second part: The temperature required to change the volume of the gas sample is 347 °C

Explanation:

We assume the Charles - Gay Lussac law where, in constant pressure, volume of a gas changes directly proportional to Temperature (in Kelvin)

V1 / T1  = V2/T2

37°C + 273 = 310 K

82°C + 273 = 355 K

1560L / 310°K = V2 / 355K

(1560 / 310) . 355 = V2

1786 L = V2

1560 L / 310 K = 3120 L / T2

T2 = 3120 L . (310 K / 1560 L)

T2 = 620 K

620K - 273 = 347°C

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